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13.E: Homework Chapter 13 Answers
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Solutions, Solvents, and Solutes:
1. a.) Solution: a homogeneous mixture composed of two or more substances
b.) Solvent: the major component in a solution
c.) Solute: the minor component in a solution
3. The two substances will not mix together. Imagine mixing oil and water together, the oil will float to the top of the water, and not mix together. This would not be a solution, this would be a heterogeneous mixture.
5. Solvent: ethyl alcohol; Solute: water
7. Solvent: water; Solute: sodium hydroxide
9. c.) CH 3 CH 2 CH 2 CH 3 *remember: “like dissolves like,” butane is nonpolar like grease*
11. 25. 2 45g KNO 3
13. 19. 9 12 g CO 2
15. 2.0 8 12 mol Al; Aluminum is the solute.
17. The solution would be unsaturated, because at 25 degrees Celsius, the point would fall below the solubility curve, indicating that it is unsaturated.
Mass Percent Calculations:
19. = 33. 7 %
21. a.) 4.5 2 %
b.) 10. 9 %
c.) 9.0 9 %
27. 29. 7 %
29. 6.0 8 %
Molarity Calculations:
31. a.) 077 8 M
b.) 0.10 8 M
c.) 0.052 1 M
d.) 0.49 3 M
33. 0.25 5 g KCl
35. 0.75 2 M
37. 0.034 4 M
39. 7.6 8 M
Dilution Calculations:
41. M 2 = 7.0 5 M
43. V 1 = 12. 5 mL
45. You would need to take 3.00mL of the 10.0 M stock solution and dilute it to 15.0 mL.
47. a.) V 2 = 18.0 mL
b.) V 2 = 14.0 mL
c.) V 2 =52.5 mL
d.) V 2 = 40.0 mL
49. V 2 = 18. 5 45 L
51. V 2 = 125 mL
53. a.) M 1 = 5.00 M
b.) M 1 = 6.00 M
c.) M 1 = 7.50 M
d.) M 1 = 5.7 6 92 M
55. M 1 = 3.5 0 M
57. V 2 = 24. 0 mL
Cumulative/Challenge Problems:
59. Solvent: soap; Solute: water
61. M 2 = 1.6 7 M
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A solution is prepared by adding 1.77 grams of sodium nitrate, 2.4 grams of potassium chloride, and 0.973 grams of ammonium nitrite to 255 grams of water. Calculate the total mass of the solution and express the sum in the proper number of significant figures. d. 4. Consider that 1 in. = 2.54 cm.
(a) Determine the molar mass of KMnO 4; determine the number of moles of KMnO 4 in the solution; from the number of moles and the volume of solution, determine the molarity; (b) 1.15 × × 10 −3 M 55 .
In geometric patterns with long range, repeating order. 5. Chemical change. 7. No, the law of conservation of mass. 9. The measure of thermal energy. 11. Element and compound.
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MasteringChemistry with Pearson eText Student Access Code Card for Chemistry | 6th Edition ISBN-13: 9780321723437 ISBN: 0321723430 Authors: - Pearson, Jeffrey Pearson, Robert C. Fay, John C McMurry Rent | Buy
Chapter. CH3. Problem. 1PE. Step-by-step solution. Step 1 of 4. In order to find the average atomic mass of copper, we need to convert the given percentage abundance into fractional values and then summing of amount of each isotope contribution to the total mass gives the average mass. Step 2 of 4.
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Step-by-step solution. Step 1 of 2. a) In order to add numbers expressed in scientific notation, the exponents must be the same. This means that the decimal points must be aligned before you add the numbers. Once the numbers have the same exponent, the coefficients can be added. This sum of the coefficient is then multiplied by 10 raised to the ...
Chemistry Homework Answers Chapter 3 - Free download as PDF File (.pdf), Text File (.txt) or read online for free. chemistry homework answers chapter 3
VIEW FULL DOCUMENT. Please read the Introduction first, then click on the video to view the clip in its entirety before answering the questions below. Use the scroll bar to view and answer all five questions before clicking "Submit Answer" to see your feedback. After you rece ive your feedback, click "Submit for Grading.".
Fall 2023 CHEM 120-Acid Base Post lab Assignment-M-Th. Chemistry document from San Diego City College, 8 pages, Homework-Chapters 1, 2, and 3 Chem152 Haggard Chapter 1 - Introduction 1. Define matter and how chemistry is the study of matter. Matter is anything that has mass and takes up space, described in physical and chemical properties.
The bond length of the atom is the distance between the centres of two covalently bonded atoms. It is generally expressed either in nanometres (nm), picometres (pm), or angstroms. Step 2 of 5. Useful Conversion. Step 3 of 5. Solution. (a) As, Using the above formula, bond length can be calculated in metres (m).
In geometric patterns with long range, repeating order. 5. Chemical change. 7. No, the law of conservation of mass. 9. The measure of thermal energy. 11. Element and compound.
1. A carbon atom can form up to four covalent bonds. (Click to select) True False 2. A carbon atom has six electrons in its outermost shell. (Click to select) True False 3. The bond between a carbon and hydrogen atom is a polar covalent bond. (Click to select) True False 4. Oxygen and nitrogen have a stronger electronegativity than carbon (e.g ...
The reaction can be written as follows: Step 2 of 3. (b) Ethanol reacts with sodium hydride and it forms an ethoxide ion in the product and hydrogen gas is liberated. The reaction can be written as follows: Step 3 of 3. Ethane is a saturated hydrocarbon. The bond in ethanol is polar and reacts with and. However, the bond in ethane is not polar ...
1. a.) Solution: a homogeneous mixture composed of two or more substances. b.) Solvent: the major component in a solution. c.) Solute: the minor component in a solution. 3. The two substances will not mix together. Imagine mixing oil and water together, the oil will float to the top of the water, and not mix together.