lesson 9 homework answer key grade 5 pdf

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McGraw Hill My Math Grade 5 Chapter 9 Lesson 5 Answer Key Add Unlike Fractions

All the solutions provided in McGraw Hill Math Grade 5 Answer Key PDF Chapter 9 Lesson 5 Add Unlike Fractions  will give you a clear idea of the concepts.

McGraw-Hill My Math Grade 5 Answer Key Chapter 9 Lesson 5 Add Unlike Fractions

Math in My World

Helpful Hint The least common denominator, LCD, is the least common multiple of the denominators.

Guided Practice

Add. Write each sum in simplest form.

Independent Practice

Question 4. \(\frac{1}{2}\) + \(\frac{1}{5}\) = _____ Answer: The above-given unlike fractions: 1/2 + 1/5 Here the denominators are unequal, so make them equal first. Step 1: Make the denominators equal. 10 is the least common multiple of denominators 2 and 5. Use it to convert to equivalent fractions with this common denominator. 1/2 + 1/5 = 1 x 5/2 x 5 + 1 x 2/5 x 2 .                = 5/10 + 2/10 Here, the denominators are equal, so we can add. .                = 5 + 2/10 .                = 7/10 Therefore, \(\frac{1}{2}\) + \(\frac{1}{5}\) = 7/10

Question 5. \(\frac{5}{12}\) + \(\frac{1}{4}\) = _____ Answer: The above-given unlike fractions: 5/12 + 1/4 Here the denominators are unequal, so make them equal first. Step 1: Make the denominators equal. 12 is the least common multiple of denominators 12 and 4. Use it to convert to equivalent fractions with this common denominator. 5/12 + 1/4 = 5 x 1/12 x 1 + 1 x 3/4 x 3 .                  = 5/12 + 3/12 Here, the denominators are equal, so we can add. .                 = 5 + 3/12 .                 = 8/12 We can reduce the fractions here. – Reduce the fraction to the lowest terms 4 is the greatest common divisor of 8 and 12. Reduce by dividing both the numerator and denominator by 4. 8/12 = 8 ÷ 4/12 ÷ 4 .        = 2/3. Therefore, \(\frac{5}{12}\) + \(\frac{1}{4}\) = 2/3.

Question 6. \(\frac{2}{3}\) + \(\frac{1}{6}\) = _____ Answer: The above-given unlike fractions: 2/3 + 1/6 Here the denominators are unequal, so make them equal first. Step 1: Make the denominators equal. 6 is the least common multiple of denominators 3 and 6. Use it to convert to equivalent fractions with this common denominator. 2/3 + 1/6 = 2 x 2/3 x 2 + 1 x 1/6 x 1 .                = 4/6 + 1/6 Here the denominator is equal so that we can add them. .               = 4 + 1/6 .               = 5/6 Therefore, \(\frac{2}{3}\) + \(\frac{1}{6}\) = 5/6

Question 7. \(\frac{1}{2}\) + \(\frac{1}{4}\) = _____ Answer: The above-given unlike fractions: 1/2 + 1/4 Here the denominators are unequal, so make them equal first. Step 1: Make the denominators equal. 4 is the least common multiple of denominators 2 and 4. Use it to convert to equivalent fractions with this common denominator. 1/2 + 1/4 = 1 x 2/2 x 2 + 1 x 1/4 x 1 .                = 2/4 + 1/4 Here the denominator is equal so that we can add them. .                 = 2 + 1/4 .                 = 3/4 Therefore, \(\frac{1}{2}\) + \(\frac{1}{4}\) = 3/4

Question 8. \(\frac{5}{8}\) + \(\frac{1}{16}\) = _____ Answer: The above-given unlike fractions: 5/8 + 1/16 Here the denominators are unequal, so make them equal first. Step 1: Make the denominators equal. 16 is the least common multiple of denominators 8 and 16. Use it to convert to equivalent fractions with this common denominator. 5/8 + 1/16 = 5 x 2/8 x 2 + 1 x 1/16 x 1 .                  = 10/16 + 1/16 Here the denominator is equal so that we can add them. .                = 10 + 1/16 .                = 11/16 Therefore, \(\frac{5}{8}\) + \(\frac{1}{16}\) = 11/16

Question 9. \(\frac{3}{5}\) + \(\frac{3}{10}\) = _____ Answer: The above-given unlike fractions: 3/5 + 3/10 Here the denominators are unequal, so make them equal first. Step 1: Make the denominators equal. 10 is the least common multiple of denominators 5 and 10. Use it to convert to equivalent fractions with this common denominator. 3/5 + 3/10 = 3 x 2/5 x 2 + 3 x 1/10 x 1 .                  = 6/10 + 3/10 Here the denominator is equal so that we can add them. .                  = 6 + 3/10 .                  = 9/10 Therefore, \(\frac{3}{5}\) + \(\frac{3}{10}\) = 9/10

Question 10. \(\frac{5}{8}\) + \(\frac{3}{16}\) = _____ Answer: The above-given unlike fractions: 5/8 + 3/16 Here the denominators are unequal, so make them equal first. Step 1: Make the denominators equal. 16 is the least common multiple of denominators 8 and 16. Use it to convert to equivalent fractions with this common denominator. 5/8 + 3/16 = 5 x 2/8 x 2 + 3 x 1/16 x 1 .                 = 10/16 + 3/16 Here the denominator is equal so that we can add them. .                  = 10 + 3/16 .                  =13/16 Therefore, \(\frac{5}{8}\) + \(\frac{3}{16}\) = 13/16

Question 11. \(\frac{3}{5}\) + \(\frac{3}{20}\) = _____ Answer: The above-given unlike fractions: 3/5 + 3/20 Here the denominators are unequal, so make them equal first. Step 1: Make the denominators equal. 20 is the least common multiple of denominators 5 and 20. Use it to convert to equivalent fractions with this common denominator. 3/5 + 3/20 = 3 x 4/5 x 4 + 3 x 1/20 x 1 .                 = 12/20 + 3/20 Here the denominator is equal so that we can add them. .                = 12 + 3/20 .                = 15/20 – Reduce the fraction to the lowest terms 5 is the greatest common divisor of 15 and 20. Reduce by dividing both the numerator and denominator by 5. 15/20 = 15 ÷ 5/20 ÷ 5 .          = 3/4 Therefore, \(\frac{3}{5}\) + \(\frac{3}{20}\) = 3/4

Algebra Find each unknown.

Question 12. \(\frac{7}{12}\) + \(\frac{1}{3}\) = x x = ____ Answer: The above-given unlike fractions: 7/12 + 1/3 = x we need to find out the value of x. Here the denominators are unequal, so make them equal first. Step 1: Make the denominators equal. 12 is the least common multiple of denominators 12 and 3. Use it to convert to equivalent fractions with this common denominator. 7/12 + 1/3 = 7 x 1/12 x 1 + 1 x 4/3 x 4 .                 = 7/12 + 4/12 Now add: (7 + 4)/12 .              = 11/12 Therefore, the value of the x is 11/12.

Question 13. \(\frac{3}{16}\) + \(\frac{3}{8}\) = \(\frac{9}{y}\) y = ____ Answer: The above-give unlike fractions: 3/16 + 3/8 = 9/y we need to find out the value of y. Here the denominators are unequal, so make them equal first. Step 1: Make the denominators equal. 3/16 + 3/8 = 3 x 1/16 x 1 + 3 x 2/8 x 2 .                 = 3/16 + 6/16 Now add:  (3 + 6)/16 .              = 9/16 Therefore, the value of y is 16. 9 is the numerator and the denominator is 16.

Question 14. \(\frac{3}{16}\) + \(\frac{3}{8}\) = \(\frac{9}{w}\) w = ___ Answer: The above-given unlike fractions: 3/16 + 3/8 = 9/w Here the denominators are unequal, so make them equal first. Step 1: Make the denominators equal. 3/16 + 3/8 = 3 x 1/16 x 1 + 3 x 2/8 x 2 .                 = 3/16 + 6/16 Now add:  (3 + 6)/16 .              = 9/16 Therefore, the value of w is 16. 9 is the numerator and the denominator is 16.

Problem Solving

Question 16. Angel has two chores after school. She rakes leaves for \(\frac{3}{4}\) hour and spends \(\frac{1}{2}\) hour washing the car. How long does Angel spend on her chores in all? Answer: The above-given: The number of hours she spends on leaves = 3/4 The number of hours she spends on washing the car = 1/2 The total hours she spends = t t = 3/4 + 1/2 Here the denominators are unequal, so make them equal first. Step 1: Make the denominators equal. t = 3 x 1/4 x 1 + 1 x 2/2 x 2 t = 3/4 + 2/4 Now denominators are equal so that we can add the fractions. t = 3 + 2/4 t = 5/4 In mixed fraction, we can write it as 1 1/4.

HOT Problems

Question 17. Mathematical PRACTICE 2 Use Number Sense Leon found the sum of \(\frac{5}{6}\) and \(\frac{2}{3}\) to be \(\frac{11}{12}\). How can you tell that his answer is incorrect without calculating? Answer: According to the above-given problem the equation is: 5/6 + 2/3 = 11/12 Here the answer is incorrect. The correct explanation is: = 5 x 1/6 x 1 + 2 x 2/3 x 2 = 5/6 + 4/6 Here the denominators are equal so that we can add. = ( 5 + 4)/6 = 9/6 Reduce the fraction to the lowest terms. 3 is the greatest common divisor of 9 and 6. Reduce by dividing both the numerator and denominator by 3. 9/6 = 9 ÷ 3/6 ÷ 3 .      = 3/2 Convert improper fractions to mixed number 3 ÷ 2 = 1 remainder 1 The mixed number is 1 1/2.

Question 19. ? Building on the Essential Question How are equivalent fractions used when adding, unlike fractions? Answer: Add and subtract fractions with unlike denominators (including mixed numbers) by replacing given fractions with equivalent fractions in such a way as to produce an equivalent sum or difference of fractions with like denominators.

McGraw Hill My Math Grade 5 Chapter 9 Lesson 5 My Homework Answer Key

Question 1. \(\frac{5}{8}\) + \(\frac{3}{10}\) = ____ Answer: The above-given unlike fractions: 5/8 + 3/10 Here the denominators are unequal, so make them equal first. Step 1: Make the denominators equal.

Question 2. \(\frac{3}{5}\) + \(\frac{1}{4}\) = ____ Answer: The above-given unlike fractions: 3/5 + 1/4 Here the denominators are unequal, so make them equal first. Step 1: Make the denominators equal.

Question 3. \(\frac{4}{7}\) + \(\frac{1}{8}\) = ____ Answer: The above-given unlike fractions: 4/7 + 1/8 Here the denominators are unequal, so make them equal first. Step 1: Make the denominators equal.

Question 4. Tashia ate \(\frac{1}{3}\) of a pizza, and Jay ate \(\frac{3}{8}\) of the same pizza. What fraction of the pizza was eaten? Answer: The above-given: The amount of pizza Tashia ate = 1/3 The amount of pizza Jay ate = 3/8 The fraction of pizza eaten = e e = 1/3 + 3/8 Find common denominator 24 is the least common multiple of denominators 3 and 8. Use it to convert to equivalent fractions with this common denominator. e = 1 x 8/3 x 8 + 3 x 3/8 x 3 e = 8/24 + 9/24 Now add: (8 + 9)/24 e = 17/24 Therefore, the fraction is 17/24.

Question 5. Basir took a science test on Friday. One-eighth of the questions were multiple choice, and \(\frac{3}{4}\) of the questions were true-false questions. What part of the total number of questions are either multiple-choice or true-false questions? Answer: The above-given: The number of multiple questions = 1/8 The number of true-false questions = 3/4 The part of the total number of questions = q q = 1/8 + 3/4 Find common denominator 8 is the least common multiple of denominators 8 and 4. Use it to convert to equivalent fractions with this common denominator. q = 1 x 1/8 x 1 + 3 x 2/4 x 2 q = 1/8 + 6/8 q = 7/8 Therefore, the fraction is 7/8.

Question 6. Mathematical PRACTICE 2 Use Number Sense Edison delivers \(\frac{1}{5}\) of the newspapers in the neighbourhood, and Anita delivers \(\frac{1}{2}\) of them. Together, Edison and Anita deliver what fraction of the newspapers? Answer: The newspapers delivered by Edison = 1/5 The newspapers delivered by Anita = 1/2 Together delivered = d d = 1/5 + 1/2 Find common denominator 10 is the least common multiple of denominators 5 and 2. Use it to convert to equivalent fractions with this common denominator. d = 1 x 2/5 x 2 + 1 x 5/2 x 5 d = 2/10 + 5/10 d = 2 + 5/10 d = 7/10 Therefore, together delivered 7/10 newspapers.

Test Practice

Question 8. Which expression will have the same sum as \(\frac{3}{8}\) + \(\frac{1}{4}\)? A. \(\frac{3}{8}\) + \(\frac{1}{8}\) B. (\(\frac{1}{8}\) + \(\frac{1}{8}\) + \(\frac{1}{8}\)) + \(\frac{1}{4}\) C. \(\frac{3}{4}\) + \(\frac{1}{4}\) D. (\(\frac{1}{8}\) + \(\frac{1}{8}\)) + \(\frac{1}{8}\) Answer: Option B is correct. The above-given: 3/8 + 1/4 The answer is 5/8 Now come to the options: Option A: 3/8 + 1/8 = 4/8 = 1/2 Option B: (1/8 + 1/8 + 1/8) + 1/4 3/8 + 1/4 = 5/8 Option C: 3/4 + 1/4 = 4/4 = 1 Option D: 1/8 + 1/8 + 1/8 = 3/8 Therefore, the correct answer is option B.

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Texas Go Math Grade 5 Lesson 9.1 Answer Key Formulas for Area and Perimeter

Refer to our Texas Go Math Grade 5 Answer Key Pdf to score good marks in the exams. Test yourself by practicing the problems from Texas Go Math Grade 5 Lesson 9.1 Answer Key Formulas for Area and Perimeter.

Unlock the Problem

A formula is an equation that expresses a mathematical rule. You can use formulas to find the perimeter and area of rectangles.

Lloyd is planting a rectangular garden that measures 40 feet by 24 feet. He wants to put a fence around it to protect his vegetables from rabbits. How many feet of fencing does he need?

Use a formula to find the perimeter. P = l + w + l + w, P = perimeter; l = length; w = width P = 40 + ___24____ + __40_____ + ___24____ Replace the unknowns with the lengths and the widths. P = ___128____ Add. The perimeter is ___128____ feet. So, Lloyd needs ___128____ feet of fencing.

Remember Area is measured in square units, such as square feet or sq ft. Answer: The perimeter is 128 feet, So Lloyd needs 128 feet of fencing,

Explanation: Lloyd is planting a rectangular garden that measures 40 feet by 24 feet. He wants to put a fence around it to protect his vegetables from rabbits. So number of feet of fencing does he need is using a formula to find the perimeter P = l + w + l + w, P = perimeter; l = length; w = width is P= 40 + 24 + 40 + 24 = 128 feet, So Lloyd needs 128 feet of fencing.

Lloyd needs to find how large his garden is so he can order enough mulch for the garden. What is the area of Lloyd’s garden?

Use a formula to find the area. A = l × w, A = area; I = length; w = width A = ____40____ × __24_____ Replace the unknowns with the length and the width. A = ____960_______ Multiply. So, the area of Lloyd’s garden is _____960___ square feet. Answer: The area of the garden is 960 square feet,

Explanation: Given Lloyd is planting a rectangular garden that measures length 40 feet by width 24 feet, therefore the area of Lloyd’s garden is 40 X 24 = 960 square feet.

You can also use the formula P = 2l + 2w to find the perimeter. What is the perimeter of a rectangle that is 12 feet long and 16 feet wide? P = 2 × ____12_____ + 2 × ___16_______ Replace the unknowns with the length and the width. P = __24 + 32_______ The perimeter is ___56___ feet. Answer: The perimeter is 56 feet,

Explanation: Given to find the perimeter of a rectangle that is 12 feet long and 16 feet wide, by using the formula p = 2l + 2w, so p = 2 X 12 + 2 X 16, p = 24 + 32, p = 56 feet. therefore the perimeter is 56 feet.

Math Talk Mathematical Processes

Explain how you can use the properties of operations to write P = l + w + l + w as P = 2l + 2w. Answer: By using properties of operations addition we write p = l + w + l + w as P = 2l + 2w,

Explanation: Given to write p = l + w + l + w by using properties of operations addition we add common terms l with l and w with w we get p = (l + l) + (w + w), p = 2l + 2 w.

STEP 1: Separate the figure into a rectangle and a square.

STEP 2: Find the area of the rectangle. A = l × w A = __3 X 3_________ A = ___9________ The area of the rectangle is _____9______ square meters.

STEP 3: Find the area of the square. A = ___5 X 4________ A = ____20_______ A = ___________ The area of the square is _____20______ square meters.

STEP 4: Find the area of the complex figure by adding the areas. A = ____9_______ + ___20________ A = ____29_______ So, the area of the complex figure is ____29_______ square meters. Answer: The area of the complex figure is 29 square meters,

Explanation: STEP 1: Separate the figure into a rectangle and a square, STEP 2: Finding the area of the rectangle as A = l × w, A = 3 X 3, A = 9, The area of the rectangle is 9 square meters, STEP 3: Finding the area of the square A = 5 X 4, A = 20, The area of the square is 20 square meters.

STEP 4: Find the area of the complex figure by adding the areas. A = 9 + 20, A = 29, So, the area of the complex figure is 29 square meters.

Share and Show

Explanation: Given the side of the square is 14 meters, therefore the perimeter of a square is 14 + 14 + 14 + 14 = 56 meters.

Problem Solving

Question 3. H.O.T. Explain how you can use s to write the formula for the perimeter of a square with side length s. Answer: Perimeter= 4s,

Explanation: Given s to write the formula for the perimeter of a square with side length s is s + s + s + s =  4s.

Question 4. H.O.T. A rectangle has an area of 96 square feet. If the length of the rectangle is 12 feet, what is the width of the rectangle? Answer: 8 feet is the width of the rectangle,

Explanation: Given a rectangle has an area of 96 square feet. If the length l of the rectangle is 12 feet, let w be the width of the rectangle as we know area of rectangle is A = l X w substituting 96 square feet= 12 feet X w, w = 96 square feet  ÷ 12 feet = 8 feet.

Question 5. Brent plans to stain a deck that is 14 feet by 8 feet. If one can of stain covers an area of 100 square feet, how many cans of stain will he need? Explain. Answer: 2 cans of stain Brent need,

Explanation: Brent plans to stain a deck that is 14 feet by 8 feet. If one can of stain covers an area of 100 square feet, So a deck is of area 14 feet X 8 feet = 112 square feet  as one can of stain covers an area of 100 square feet therefore  number of cans of stain Brent will need is 2.

Explanation: Latoya uses 50 feet of wood to make a rectangular garden bed, So number of feet of fencing does he need is using a formula for finding the perimeter P = l + w + l + w, P = perimeter; l = length; w = width is 50 = 10 + w + 10 + w upon solving we get 2w = 50 – 20 = 30, 2 w = 30 therefore w = 30 ÷ 2 = 15 feet.

Explanation: Given Maggie wants to fence off two side-by-side sections of her garden and each section is 14 feet long and 6 feet wide, She says she needs 80 feet of fencing, but wrong with her thinking, as if we see 80 feet(14 + 6 + 14 + 6) will cover only one section off the garden fence for two side-by-side sections of her garden she needs 2 X 80 feet = 160 feet.

Daily Assessment Task

Fill in the bubble for the correct answer choice.

Question 8. Apply Tina is fixing a rectangular sign. She plans to place metal trim around the sign edges. The rectangle measures 32 inches by 9 inches. How much trim will Tina need? (A) 36 inches (B) 41 inches (C) 72 inches (D) 82 inches Answer: (D) 82 inches,

Explanation: Given Tina is fixing a rectangular sign. She plans to place metal trim around the sign edges. The rectangle measures 32 inches by 9 inches. So trim will Tina need is 32 inches + 9 inches + 32 inches + 9 inches = 82 inches which matches with (D).

Question 9. A rectangle has a length of 5 meters and a width of 4 meters. Which equation can you use to find the perimeter? (A) P = 4 × 5 (B) P = 4 × 4 (C) P = 4 + 4 + 5 + 5 (D) P = 4 + 5 Answer: (C) P = 4 + 4 + 5 + 5,

Explanation: Given rectangle has a length of 5 meters and a width of 4 meters we know perimeter P = l + w + l + w, where P = perimeter; l = length; w = width so we get the equation to find the perimeter is P = 4 + 4 + 5 + 5 which matches with (C).

5th Grade Math Formulas for Area and Perimeter Lesson 9.1 Answer Key Question 10. Multi-Step Lana had an “L” shaped piece of felt. Her mom cut it into two rectangles. One rectangle measured 4 inches by 9 inches, and the other measured 4 inches by 3 inches. What is the total area of the two rectangles? (A) 40 square inches (B) 48 square inches (C) 72 square inches (D) 24 square inches Answer: (B) 48 square inches,

Explanation: Given Lana had an “L” shaped piece of felt. Her mom cut it into two rectangles. One rectangle measured 4 inches by 9 inches, and the other measured 4 inches by 3 inches. So area of one rectangle is 4 inches X 9 inches = 36 square inches, other area of rectangle is 4 inches X 3 inches = 12 square inches, so the total area of the two rectangles is 36 square inches + 12 square inches = 48 square inches which matches with (B).

TEXAS Test Prep

Question 11. Mai wants to tile the floor of her kitchen. Each tile has an area of 1 square foot. The floor of her kitchen is 11 feet by 16 feet. How many tiles does she need? (A) 150 (B) 54 (C) 176 (D) 352 Answer: (C) 176,

Explanation: Given Mai wants to tile the floor of her kitchen. Each tile has an area of 1 square foot. The floor of her kitchen is 11 feet by 16 feet. So total area of Mai kitchen is 11 feet X 16 feet = 176 square foot matches with (c).

Texas Go Math Grade 5 Lesson 9.1 Homework and Practice Answer Key

Explanation: Given rectangle has a length of 21 feet and a width of 15 feet we know perimeter P = l + w + l + w, where P = perimeter; l = length; w = width so the perimeter of rectangle is P = 21 + 15 + 21 + 15 = 72 feet.

Explanation: Given the side of the square is 17 inches, the area of square is 17 inches X 17 inches = 289 square inches.

Question 3. A rectangle has a perimeter of 68 inches. 1f the width of the rectangle is 10 inches, what is the length of the rectangle? Explain how you know. Answer: The length of the rectangle is 24 inches,

Explanation: Given a rectangle that has a perimeter of 68  inches. If the width of the rectangle is 10 inches, let l be the length of the rectangle as we know perimeter P = l + w + l + w, where P = perimeter; l = length; w = width so the length of rectangle l is 68 = 10 + 10 + l + l, so 2l = 68 – 20 = 48, l = 48 ÷ 2 = 24 inches.

Question 4. A square has an area of 81 square feet. What is the length of each side of the square? Explain how you know. Answer: The length of side of the square is 9 feet,

Explanation: Given a square has an area of 81 square feet. The length of each side of the square will be as area of square is s X s , so 81 square feet = s X s, s X s = 9 feet X 9 feet , therefore s = 9 feet.

Question 5. Lea wants to put a fence around her garden. Her garden measures 14 feet by 15 feet. She has 50 feet of fencing. How many more feet of fencing does Lea need to put a fence around her garden? Answer:

Go Math Grade 5 Lesson 9.1 Formulas of Area and Perimeter Question 6. Lea wants to put a new layer of soil on her 14 feet by 15 feet garden. She finds the area of her garden so she knows how much soil to buy. If one bag of soil covers 20 square feet, how many bags of soil will Lea need? Explain. Answer: 11 bags of soil Lea needs,

Explanation: Given Lea wants to put a new layer of soil on her 14 feet by 15 feet garden. She finds the area of her garden as 14 feet X 15 feet = 210 square feet, she knows how much soil to buy If one bag of soil covers 20 square feet, 210 square feet requires 210 ÷ 20 = 10 bags remainder 10 square feet, therefore 11 bags of soil Lea needs.

Lesson Check

Fill in the bubble completely to show your answer.

Question 7. A soccer field has a length of 100 yards and a width of 60 yards. Which equation can you use to find the area of the soccer field? (A) A = 100 × 60 (B) A = 100 + 60 + 100 + 60 (C) A = 100 + 60 (D) A = 160 × 4 Answer: (A) A = 100 × 60,

Explanation: Given a soccer field has a length of 100 yards and a width of 60 yards, as we know area of square is Area is equal to length X width so the equation for the area of the soccer field is A = 100 X 60 which matches with (A).

Question 8. A baseball diamond is a square with a perimeter of 360 feet. What is the length of one side? (A) 80 feet (B) 180 feet (C) 90 feet (D) 60 feet Answer: (C) 90 feet,

Explanation: Given a baseball diamond is a square with a perimeter of 360 feet. So the length of one side will be as perimeter of square with side s is p = 4s so 360 feet = 4 X s, therefore one side is 360 ÷ 4 = 90 feet matches with (C).

Question 9. Zoey wants to cover her bedroom floor with carpet squares. Each square has an area of 1 square foot. Her bedroom measures 12 feet by 14 feet. How many carpet squares does Zoey need? (A) 168 (B) 144 (C) 336 (D) 52 Answer: (A) 168,

Explanation: Given Zoey wants to cover her bedroom floor with carpet squares. Each square has an area of 1 square foot. Her bedroom measures 12 feet by 14 feet. So number of squares does Zoey need is 12 X 14 = 168 square feet matches with (A).

Go Math Homework Lesson 9.1 Area and Perimeter Answer Key Question 10. Edward wants to put a string of lights around a rectangular window that is 32 inches wide and 40 inches high. How long will the string of lights need to be to go around the window? (A) 72 inches (B) 1,280 inches (C) 144 inches (D) 112 inches Answer: (B) 1,280 inches,

Explanation: Given Edward wants to put a string of lights around a rectangular window that is 32 inches wide and 40 inches high. The string of lights need to be to go around the window is 32 X 40 = 1,280 inches matches with (B) 1,280 inches.

Question 11. Multi-Step Chantal buys two small rugs for her kitchen. One rug measures 3 feet by 5 feet. The other rug measures 4 feet by 6 feet. What is the area of the part of the kitchen the two rugs will cover? (A) 39 square feet (B) 30 square feet (C) 24 square feet (D) 36 square feet Answer: (A) 39 square feet,

Explanation: Given Chantal buys two small rugs for her kitchen. One rug measures 3 feet by 5 feet. The other rug measures 4 feet by 6 feet. First rug covers 3 feet by 5feet is 5 X 3 = 15 square feet, Other rug covers 4 feet by 6 feet is 4 X 6 = 24 square feet, The area of the part of the kitchen the two rugs will cover is 15 square feet + 24 square feet = 39 square feet.

Area and Perimeter 5th Grade Lesson 9.1 Homework Answer Key Question 12. Multi-Step Isaac is painting a wall that is 9 feet by 18 feet. So far, he has painted a part of the wall that is a 4 feet by 7 feet rectangle. What is the area of the part of the wall that Isaac has left to paint? (A) 190 square feet (B) 134 square feet (C) 22 square feet (D) 151 square feet Answer: (B) 134 square feet,

Explanation: Given Isaac is painting a wall that is 9 feet by 18 feet. So far, he has painted a part of the wall that is a 4 feet by 7 feet rectangle. Total area of the wall is 9 feet X 18 feet = 162 square feet, Part of the wall painted is 4 feet by 7 feet = 28 square feet, The area of the part of the wall that Isaac has left to paint is 162 square feet – 28 square feet = 134 square feet matches with (B).

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Assessments and Learning The “competitive incorrect answers” are related material, just not the correct answer. Thinking about them, though, strengthens what students know about those items. In later assessment situations, when a new question is asked and a previous competitive …

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Jump into Spring Break! Spring break is a time to relax, and enjoy the warmer weather. It is a time when you and your students can recharge, so when you return you are ready to tackle the last few months …

Thanksgiving Math

We are so thankful for the third, fourth, and fifth-grade students (and teachers) who use our books, we created a Thanksgiving-themed makeover to our Simple Solutions Standards-Based Math sample pages. Each lesson in the Simple Solutions Standards-Based Mathematics workbook aligns with standards for …

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Math Expressions 5, Volume 1, Grade: 5 Publisher: Houghton Mifflin Harcourt

Math expressions 5, volume 1, title : math expressions 5, volume 1, publisher : houghton mifflin harcourt, isbn : 054705727x, isbn-13 : 9780547057279, use the table below to find videos, mobile apps, worksheets and lessons that supplement math expressions 5, volume 1., textbook resources.

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